Wednesday, April 24 Manchester city beat arch-rival “Manchester United” with the score 2:0.
Ukrainian footballer Oleksandr Zinchenko , came out in the starting lineup of the bulls and was recognized as one of the best players. Now the “Manchester city” have to win three matches to get the title. All will depend on how they play “Burnley”, “Lester” and “Brighton”.
British media jokingly write that the fate of the title depends on two people: Josep Guardiola and Alexander Zinchenko. The Spanish coach determines the starting lineup for the game, a Ukrainian football player became a kind of mascot for the bulls, reports Footboom.
The fact that Zinchenko, came out in England in the “city” 19 times, and all 19 games his team won. It all started on 13 December 2017, when Alexander came on as a substitute in the match against Swansea. A 73 minute Ukrainian has replaced Fabian Delphi, and the bulls won 4:0.
Since, if Zinchenko, came out in the first team or on the bench, then city have won the match. That is why in England people are already writing about the fact that if Zinchenko will play his 20th (“Burnley”), 21st (“Lester”) and 22nd (with “Brighton”) matches in the EPL, then Manchester city all these games win, a unique series of winning matches with Alexander in the composition will last, and the bulls can win the championship of England.
22-year-old Ukrainian has played 25 matches for Manchester city in all competitions this season, scored 1 goal and 5 assists.
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